Question 1199494
3x+2y=8
x^2+y^2=8
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3x+2y=8 ---> y = -(3/2)x + 4
y^2 = (9x^2/4) - 12x + 16
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x^2+y^2=8
Sub for y^2
x^2 + (9x^2/4) - 12x + 16 = 8
4x^2 + 9x^2 - 48x + 32 = 0
13x^2 - 48x + 32 = 0
*[invoke solve_quadratic_equation 13,-48,32]
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Sub for x in 3x+2y=8 and find y.
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Use F6 to enter the given relationships.