Question 114572
First convert 2x-3y=-7 to slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 2, -3, -7, 2, 1]


Now let's find the equation of the line through points (6,-2) that is  perpendicular to {{{y=(2/3)x+7/3}}}

*[invoke equation_parallel_or_perpendicular "perpendicular", "2/3", "7/3", 6, -2]