Question 1199402
You did not finish the problem description or did not write what question to answer.   You can expect that the 
distance is the same value  in each direction.
<pre>
                 SPEED         TIME           DISTANCE

GOING TO            96
COMING BACK        100

TOTAL                           5.1
</pre>


You might continue:
<pre>
                 SPEED         TIME           DISTANCE

GOING TO            96         5.1-x          96(5.1-x)
COMING BACK        100          x            100x

TOTAL                           5.1
</pre>

You should understand that both directions being same length,
{{{highlight_green(96(5.1-x)=100x)}}}.

Solve for the time "coming back", and then evaluate time "going to" and the distance either direction.

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{{{(96)(5.1)-96x=100x}}}
{{{(96)(5.1)=196x}}}
{{{x=((96)(5.1))/196}}}

{{{x=(24/49)5.1}}}

{{{x=2.498}}}

----

GOING TO, 2.602 hours, or  2 hours 36 minutes
COMING BACK, 2.498 hours, or 2 hours 30 minutes

DISTANCE BETWEEN THE CITIES, 250 kilometers