Question 1199402
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Your post seems incomplete. 
Are you wanting to know the average speed throughout the whole roundtrip? 
If so, then read on.


d = the distance from Edmonton to Lloydminster
This is some positive real number
The distance is in kilometers.


x = time taken to drive from Edmonton to Lloydminster
y = time taken to drive from Lloydminster to Edmonton
The time durations are in hours.


When going to Lloydminster, we have this equation
distance = rate*time
d = 96x
Let's isolate x
x = d/96


The return journey has this equation.
distance = rate*time
d = 100y
y = d/100


The two time durations x and y must add to the total driving time of 5.1 hours.
x+y = 5.1
d/96 + d/100 = 5.1
d/96 + d/100 = 51/10


A common multiple of 96, 100, and 10 is 9600
I simply did 96*100 = 9600


We can multiply both sides of that equation by 9600 to clear out the fractions. 
d/96 + d/100 = 51/10
9600*(d/96 + d/100) = 9600*(51/10)
100d + 96d = 48960
196d = 48960
d = 48960/196
d = 249.795918367347
d = 249.795918
This is the approximate distance, in kilometers, from Edmonton to Lloydminster.


The round-trip distance is twice that
2*249.795918 = 499.591836
This assumes Kory travels the same route each way.


To find the average speed throughout the round trip, we will then do the following:
distance = rate*time
rate = distance/time
rate = (499.591836 km)/(5.1 hrs)
rate = 97.959184
rate = 97.96 km per hour
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