<PRE><B>Question 1199401</B>
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There is one of ten possible digits 0, 1, 2 ,3, 4, 5, 6, 7, 8, 9 in each of the 3 positions.


So, the probability to get match in any (in every) single of the three positions is {{{1/10}}} = 0.1.


Therefore, the probability to get match in all three position simultaneously is  {{{(1/10)*(1/10)*(1/10)}}} = {{{(1/10)^3}}} = {{{1/1000}}}, as stated.



Regarding the $500, it depends on the price of each ticket, which (the  price) is not given in your post.


THEREFORE, we problem is not complete to answer this question about $500.



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