Question 1199387
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The depth of water in a harbour as a function of time can be described by cosine function. 
The maximum depth is 12m and the minimum is 1.5m and at t=0 , the depth is at a minimum. 
In 65 hours, the minimum depth is reached 6 times( including the times at t=0 and t=65 hours)
Write an equation to describe the depth of the water in the harbour as a function of time.
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<pre>
From the condition, the middle / (the average) depth of water is  {{{(12 + 1.5)/2}}} = {{{13.5/2}}} = 6.75 m.

The amplitude of the cosine function is  6.75-1.5 = 5.25 m.

In the interval fro t= 0 to t 65 hours, there are 5 periods, so one single period is 65/5 = 13 hours.


The minimum depth is reached at t= 0, so we should use the negative cosine function without 
horizontal shift.


Combining everything together, our function for the depth of water is

    d(t) = {{{6.75-5.25*cos(2*pi*(t/13))}}}.    <U>ANSWER</U>
</pre>

Solved.