Question 1199344
the equation is h = 5^2 + 100t + 15.
h is the height of the rocket.
t is the time in seconds.


the height of the platform is the height when t = 0 which is 15 meters high.



the height of the rocket after 4 seconds is found by replacing t with 4 and solving for h.
you get h = -5 * 4^2 + 100 * 4 + 15 = 335 meters.


the maximum height reached by the rocket is when t = -b/2a.


a = the coefficient of the t^2 term = -5
b is the coefficient of the t term = 100
c is the constant term = 15


t = -b/2a becomes t = -100 / -10 = 10
when t = 10, h = -5 * 10^2 + 100 * 10 + 15 = 515 meters.


it takes 10 seconds for the rocket to reach the maximum height.


the equation can be graphed by letting y represent h and x represent t.
here's what the graph looks like.


<img src = "http://theo.x10hosting.com/2022/122301.jpg">