Question 1199330
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ANSWER: C<br>
To see this, draw segments from the center of the small circle to the center of the large circle, and to the points of tangency of the small circle with the x- and y-axes.  Use those to determine that the radius of the large circle is<br>
{{{sqrt(2)+sqrt(2)*sqrt(2)=2+sqrt(2)}}}<br>
Then the area of the circle is (pi)(r^2) = {{{pi(2+sqrt(2))^2}}}, answer C.<br>