Question 1199316
x = the first odd integer
x + 2 = the second odd integer
x + 4 = the third odd integer.


the statement says that 


Find three consecutive odd integers where the sum of the first and two times the seconds equal to one third of the largest


the equation for that is:
x + 2 * (x + 2) = 1/3 * (x + 4)
simplify to get:
x + 2x + 4 = 1/3 * (x + 4)
simplify to get:
3x + 4 = 1/3 * (x + 4)
multiply both sides of this equation by 3 to get:
3 * (3x + 4) = x + 4
simplify to get:
9x + 12 = x + 4
subtract x from both sides of the equation and subtract 12 from both sides of this equation to get:
8x = -8
solve for x to get:
x = -1
that's your first consecutive odd integer.
your first 3 consecutive odd integers are -1, 1, 3
the problem states that sum of the first and two times the seconds equal to one third of the largest
that becomes -1 + 2 * 1 = 1/3 * 3
simplify to get:
-1 + 2 = 1
combine like terms to get:
1 = 1
this confirms the solution is correct.
your solution is that the 3 consecutive odd integers are -1, 1, 3.