Question 1199298

let first number be {{{x}}} and second number {{{y}}} 

if a first number plus twice a second number is {{{13}}}, we  have


{{{x+2y=13}}} ..........solve for {{{x}}}

{{{x=13-2y}}} ........eq.1


if twice the first number plus the second totals {{{32}}}, we  have 

{{{2x+y=32}}}..........eq.2,  substitute {{{x}}} from eq.1

{{{2(13-2y)+y=32}}}

{{{26-4y+y=32}}}

{{{26-3y=32}}}

{{{26-32=3y}}}

{{{-6=3y}}}

{{{y=-2}}}


go to


{{{x=13-2y}}} ........eq.1,  substitute {{{y}}}

{{{x=13-2(-2)}}} 

{{{x=13+4}}} 

{{{x=17}}} 


the numbers are:{{{17}}} ,{{{-2}}}