Question 1199298
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A first number plus twice a second number is 13. 
Twice the first number plus the second totals 32. 
Find the numbers
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<pre>
    x + 2y = 13     (1)

   2x +  y = 32     (2)


From equation (1),  express x = 13-2y  and substitute it into equation (2).  You will get

    2*(13-2y) + y = 32.


Simplify and find y

    26 - 4y + y = 32

    26 - 32 = 4y- y

       -6   =   3y

        y   =   -6/3 = -2.


Then x = 13 - 2y = 13 - 2*(-2) = 13 + 4= 17.


<U>ANSWER</U>.  1st number is 17.  2nd number is -2.
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Solved.