Question 1199176
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You have received three responses, all showing variations of the standard formal algebraic method for solving 2-part mixture problems like this.<br>
Here is an informal method that can be used to solve this kind of problem quickly -- if a formal algebraic solution is not required.<br>
(1) Look at the three percentages -- 2, 5.6, and 8 -- (on a number line, if it helps)
(2) observe/calculate that 5.6 is 3.6/6 = 0.6 = 3/5 of the way from 2 to 8
(3) that means 3/5 of the mixture must be the solution with the higher percentage<br>
3/5 of the total 1 liter (1000 ml) is 600ml<br>
ANSWER: 600 ml of the 8% solution and 400 ml of the 2% solution<br>
CHECK:
.08(600)+.02(400) = 48+8 = 56
.056(1000) = 56<br>