<PRE><B>Question 1199176</B>

A biologist has two brine solutions, one containing 2% salt and another containing 8% salt. How many milliliters of each solution should she mix to obtain 1 L of a solution that contains 5.6% salt?
2% solution    	  mL
8% solution    	  mL
&lt;pre&gt;Let amount of 2% salt be T
Then amount of 8% salt = 1 - T
   We then get: .02T + .08(1 - T) = .056(1)
                .02T + .08 - .08T = .056
                      .02T - .08T = .056 - .08
                           - .06T = - .024
&lt;font color = red&gt;&lt;font size = 4&gt;&lt;b&gt;Amount of 2% solution&lt;/font&gt;&lt;/font&gt;&lt;/b&gt;, or {{{highlight_green(matrix(1,10, T, &quot;=&quot;, (- .024)/(- .06), &quot;=&quot;, .4, L, &quot;=&quot;, .4(&quot;1,000&quot;), &quot;=&quot;, highlight(matrix(1,2, 400, mL))))}}}

&lt;font color = red&gt;&lt;font size = 4&gt;&lt;b&gt;Amount of 8% solution&lt;/font&gt;&lt;/font&gt;&lt;/b&gt; = .6 L = .6(1,000) = &lt;font color = red&gt;&lt;font size = 4&gt;&lt;b&gt;600 mL&lt;/font&gt;&lt;/font&gt;&lt;/b&gt;&lt;/pre&gt;</PRE>