Question 1199274
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Since the radius of the smaller circle is  {{{sqrt(2)}}} cm  (given),  it means that the distances
from its center to x- and y-axes are equal to r = {{{sqrt(2)}}} cm.


Hence, the center of the small circle is at the distance  d = {{{sqrt((sqrt(2))^2 + (sqrt(2))^2)}}} = 2 cm
from the origin of the coordinate system.


It implies that the radius of the large circle is  R = {{{2 + sqrt(2)}}} cm.


Hence, the area of the large circle is option C).
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Solved, with full explanations.