Question 1199256


 Which is an equation of the line that passes through the points 

({{{-2}}}, {{{0}}}) and ({{{-6}}}, {{{-2}}})

use given points to find a slope

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(-2-0)/(-6-(-2))}}}

{{{m=-2/(-6+2)}}}

{{{m=-2/-4}}}

{{{m=1/2}}}

use point-slope form to find equation

{{{y-y[1]=m(x-x[1])}}}.....plug in a slope and coordiates of  the  given  point 

{{{y-0=(1/2)(x-(-2))}}}

{{{y=(1/2)(x+2)}}}

{{{y=(1/2)x+(1/2)2}}}

{{{y=(1/2)x+1}}}=> your equation



{{{drawing ( 600, 600, -10, 10, -10, 10, 
circle(-2,0,.12),circle(-6,-2,.12),
locate(-2,0.5,p(-2,0)),locate(-6,-2,p(-6,-2)),

graph( 600, 600, -10, 10, -10, 10, (1/2)x+1)) }}}