Question 1199254
p = .12
q = 1 - p = .88
sample size = 100
standard error = sqrt(p * q / 100) = sqrt(.12*.88/100) = .0325 rounded to 4 decimal places.
z-score = (.095 - .12) / .0325 = -.769 rounded to 3 decimal places.
area to the left of that z-score = .2209 rounded to 4 decimal places.
that's your test alpha.
the two tailed critical alpha is .05/2 = .025 on each end.
the test alpha is greater than this, therefore the results are not significant.
the conclusion is that there is not enough evidence to support the claim that the percentage is not 12%.
H0 states that the percentage is 12%
H1 states that the percentage is not 12%.
the z-score curve looks like the following:
<img src = "http://theo.x10hosting.com/2022/121502.jpg">