Question 1199253
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Mod 12 was used because the gap from 4 to 16 is +12 (when going from row1,column1 to row3,column1). Or put another way: each row has 6 items, so two such rows have 2*6 = 12 items.


The left/right pattern repeats every 12 items.


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I'll take another approach.


Notice the third column has 6, 14, 18, 26, ...


We can extend that a bit to say: 6, 14, 18, 26, 30, ...
The 30 is from writing the next two values in row 5.


Now focus on the odd numbered terms of that sequence.
Those terms are 6, 18, 30, ...
All of which are multiples of 6. 
Specifically they are odd multiples of 6.
An odd multiple of 6 is of the form 6n, where n is some positive odd integer.


6*1 = 6
6*3 = 18
6*5 = 30
and so on.


Another thing to notice is that the rows involving 6,18,30,... all have the terms in increasing order from left to right.
This corresponds to odd numbered rows.


Let's divide 5018 over 6
5018/6 = 836.333 approximately

Rounding up to the nearest odd number gets us 837
Then,
6*837 = 5022
This value is in column 3 to keep up with the pattern mentioned above. This item is in row 837.


The value 5022 is 4 units over the target of 5018.
So we have to go to the left 4 units.
Going 2 of those units to the left gets us from column 3 to column 1.


Then we'll bump up to row 836, which will move us to column 2 in the process.
This is the third step out of 4 total.
The fourth final step gets us to column 3.


Here's a mini table showing what's going on
<table border = "1" cellpadding = "5"><tr><td></td><td>Column 1</td><td>Column 2</td><td>Column 3</td><td>Column 4</td><td>Column 5</td><td>Column 6</td><td>Column 7</td></tr><tr><td>Row 836</td><td></td><td>5019</td><td><font color=red>5018</font></td><td>5017</td><td>5016</td><td>5015</td><td>5014</td></tr><tr><td>Row 837</td><td>5020</td><td>5021</td><td>5022</td><td>5023</td><td>5024</td><td>5025</td><td></td></tr></table>
One thing I forgot to mention is that each even numbered row goes in reverse, so we'll use that fact to count down from 5019 to 5018.



Answer: <font color=red>Column 3</font>
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