Question 1199204
{{{f(x)=x^2+x-2}}}
Term to Complete The Square,  {{{(1/2)^2=1/4}}}, based on coefficient for the x term;

{{{f(x)=x^2+x+1/4-1/4-2}}}

{{{(x^2+x+1/4)-1/4-8/4}}}

{{{highlight_green(f(x)=(x+1/2)^2-9/4)}}}


Vertex,  ( -1/2, -9/4 )


To find the x  and y intercepts
{{{(x+1/2)^2-9/4=0}}}
{{{(x+1/2)^2=9/4}}}
{{{x+1/2=0+- 3/2}}}
{{{x=-1/2+- 3/2}}}---------the x-intercepts
-
{{{y=(0+1/2)^2-9/4}}}
{{{y=1/4-9/4}}}
{{{y=-8/4=-2}}}------------the y-intercept