Question 1199205
{{{y-3=(1/2)(x-5)}}}, your equation for the line in point-slope form.


R is your unknown "x" value when y=2.   If you want to ,  substitute for y, now;

{{{2-3=(1/2)(x-5)}}}

{{{-1=(1/2)(x-5)}}}

{{{-2=x-5}}}

{{{x=-2+5}}}

{{{x=3}}}------------So your unknown point on the line is  (3,2).


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{{{y=(1/2)x-5/2+3}}}

{{{y=x/2-5/2+6/2}}}

{{{highlight_green(y=x/2+1/2)}}}


{{{graph(400,400,-5,5,-5,5,x/2+1/2)}}}
The point  (3,2)  on the line?
YES