<PRE><B>Question 1199189</B>
&lt;br&gt;
To start with, we can eliminate answer choices b and c because they are even numbers, and the number of riders on the bus DECREASES at each even-numbered stop.&lt;br&gt;
The number of riders increases by 11 at every odd-numbered stop, so the number of riders will surpass 165 when the number of riders after an even-numbered stop is greater than 165-11 = 154.&lt;br&gt;
So look for the pattern of the numbers of riders after the even-numbered stops.&lt;br&gt;
After stop #2 (the 1st even-numbered stop): 11-5 = 6
After stop #4 (the 2nd even-numbered stop): 6+(11-5) = 12
After stop #6 (the 3rd even-numbered stop): 12+(11-5) = 18&lt;br&gt;
The pattern is clear: after the n-th even-numbered stop, the number of riders is 6n.&lt;br&gt;
Now find at which even-numbered stop the number of riders is greater than 154:&lt;br&gt;
6n &gt; 154
n &gt; 154/6 = 25 2/3&lt;br&gt;
It is after the 26th even-numbered stop that the number of riders is first greater than 154.&lt;br&gt;
The 26th even numbered stop is stop number 52; so it is after the 53rd stop that the number of riders first surpasses 165.&lt;br&gt;
ANSWER: d) 53&lt;br&gt;
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