<PRE><B>Question 1199171</B>
Find the values of θ between 0° and 180° such that 2cos 3θ =3sin 3θ
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y = 2cos(3x) - 3sin(3x)
2*sqrt(1-sin^2(3x)) = 32in(3x)
4*(1- sin^2(3x) = 9sin^2(3x)
9sin^2(3x) + 4sin^2(3x) - 4 = 0
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Solve the quadratic for sin(3x)
*[invoke solve_quadratic_equation 9,4,-4]
sin(3x) = ~0.480506
3x = 28.718
x = ~ 9.57282, 170.4272 degs
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sin(3x) = ~-0.92495
3x = -22.5536 degs = 337.446 degs
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Can you do the rest?  And convert to radians?
I have a bad cold, and this is making me dizzy.</PRE>