Question 1199155
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39 inches = 39/12 = 3.25 ft
This value 3.25 is the y coordinate of point C shown below.


Diagram
*[illustration Screenshot_190.png]
Points:
A = (0, 0)
B = (12, 0)
C = (0, 3.25)
D = (4.6153846154, 2)
E = (4.6153846154, 0)
The decimal values of points D and E are approximate.


Points B and C make up the ramp.
The equation of line BC is {{{3.25x+12y = 39}}} which is of the form {{{Ax+By = C}}} (technically not standard form but somewhat close enough). It has slope {{{m = -B/A}}}


Draw a horizontal line through y = 2 which represents the height of the box.
This horizontal line intersects line BC at the point D(4.6153846154, 2).


Just below it is E(4.6153846154, 0)
The horizontal width from A(0,0) to E(4.6153846154, 0) is roughly 4.6153846154 feet.
This is unfortunately smaller than the 5 ft width of the box Henry wants to store.


Another approach would be to draw a vertical line through x = 5.
This vertical line intersects line BC at an (x,y) point such that y < 2, which means there isn't enough height for the box at this x location.


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Answer: No, there isn't enough room.
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