Question 1199113

yes, that is right so far

plug in  given  The volume {{{V}}}

{{{V=(x-2)^2 }}}

{{{4=(x-2)^2 }}}

{{{x^2 - 4x + 4 = 4}}}

{{{x^2 - 4x + 4 - 4 = 0}}}

{{{x^2 - 4x = 0}}}

{{{x(x - 4) = 0}}}


Two solutions

{{{x = 0}}}->disregard

and

{{{x = 4}}}

so, the dimensions of the sheet metal are {{{4ft}}} by {{{4ft}}}