Question 1199112
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Use two common factoring patterns.<br>
(1) {{{a^2+b^2=(a+bi)(a-bi)}}} --> {{{25x^2+144=(5x)^2+(12)^2=(5x+12i)(5x-12i)}}}<br>
(2) {{{a^3+b^3=(a+b)(a^2-ab+b^2)}}} --> {{{27x^3+125y^3=(3x)^3+(5y)^3=(3x+5y)((3x)^2-(3x)(5y)+(5y)^2)=(3x+5y)(9x^2-15xy+25y^2)}}}<br>
ANSWER: D<br>