Question 1199101
<br>
{{{y=x^2+4x-3}}}<br>
Complete the square to put the equation in vertex form.  Vertex form is<br>
{{{y=(1/(4p))(x-h)^2+k}}}<br>
The vertex is (h,k); p is the directed distance from the directrix to the vertex and from the vertex to the focus.<br>
{{{y=(x^2+4x+4)-3-4}}}
{{{y=(x+2)^2-7}}}<br>
The vertex is (-2,-7); 1/(4p) = 1, so p = 1/4.<br>
The parabola opens upward, so the focus is p units above the vertex: -7 + 1/4 = -6.75.<br>
ANSWER A) (-2,-6.75)<br>