Question 1198963

 
using the following formula:

{{{A=P(1+r/n)^(n*t)}}}

given:

{{{A=5050}}}
{{{P=3500}}}
{{{t=10}}}
{{{n=4}}}


{{{5050=3500(1+r/4)^(4*10)}}}

{{{5050/3500=(1+r/4)^40}}}

{{{(1+r/4)^40=101/70}}}

{{{log((1+r/4)^40)=log(101/70)}}}

{{{40log((1+r/4))=log(101/70)}}}

{{{log((1+r/4))=log(101/70)/40}}}

{{{log(r/4 + 1) = -log(2)/40 - log(5)/40 - log(7)/40 + log(101)/40}}}

{{{log(r/4 + 1) = 0.009165631869797533}}}

{{{r}}}≈{{{0.036831}}}

{{{r=3.6831}}}%