Question 1198721
Given cos theta = -1/5 and tan theta < 0, find cot theta and sin theta.
<pre>As usual, IGNORE everything that that woman states. If you don't, you'll be as confused as you've never been before.
MOST of what she has written is WRONG, and should therefore be DUMPED in the GARBAGE/TOILET!! She even implies that
sin is negative in the 2nd quadrant. How RIDICULOUS and heart-wrenching!!

As cos and tan are negative (< 0), {{{theta}}} is in the 2<sup>nd</sup> quadrant.

GIVEN: {{{matrix(1,9, cos (theta), "=", - 1/5, "=", A/H, "=", x/r, "=", (- 1)/5)}}}, and {{{tan (theta) < 0}}}) 

        So, {{{matrix(4,3, y^2, "=", r^2 - x^2, y^2, "=", 5^2 - (- 1)^2, y, "=", sqrt(24), y, "=", 2sqrt(6))}}}

       {{{highlight_green(matrix(1,13, highlight(cot (theta)), "=", A/O, "=", x/y, "=", (- 1)/2sqrt(6), "=", ((- 1)/2sqrt(6))(sqrt(6)/sqrt(6)), "=", (- 1sqrt(6))/2(6), "=", highlight(- sqrt(6)/12)))}}}

       {{{highlight_green(matrix(1,7, highlight(sin (theta)), "=", O/H, "=", y/r, "=", highlight(2sqrt(6)/5)))}}}

       THAT'S ALL there is to this!!</pre>