Question 1198986
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The tutor @Theo should have plotted y ≤ -2x+2 instead of y ≤ 2x+1
Keep in mind that his shaded regions are the opposite of what you are given, which means the unshaded white region is the final solution set. This is if we follow the method @Theo set out. This method is nice because it avoids looking at overlapping regions.


The alternative way is to graph x≤2 which has its shaded region to the left of the vertical line x = 2. The boundary is a solid line.
Overlap that with the shaded region of y > −2x+2, which has its shaded region above the dashed boundary line. These regions overlap to get what was mentioned in the previous paragraph, and what is shown below.


This is what the final graph should look like when shading just the solution set
*[illustration Screenshot_183.png]
Points in the blue shaded region satisfy both original inequalities.
We are to the left of x = 2, and above y = -2x+2
Points on the dashed line are not part of the solution set. This means the point (2,-2) isn't in the solution set.
Points on the solid boundary line, adjacent to the blue interior region, are part of the solution set.
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