Question 1198954
Strange way of putting it.


{{{q(t)=q2^(kt)}}}


If half life 300 years then
{{{1/2=1*2^(300k)}}}

{{{1/2=2^(300k)}}}

Which base do you want?  ...
{{{log((1/2))=300k*log((2))}}}

{{{300k=log((1/2))/log((2))}}}

{{{300k=-log((2))/log((2))}}}

{{{300k=-1}}}

{{{highlight(k=-1/300)}}}


The function in that form is {{{highlight(q(t)=q2^((-1/300)t))}}}.