Question 1198928
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I'll use theta in place of the variable t
theta = {{{theta}}} = Greek letter often used with angles


tan(theta) = -8/15
tan(angle) = opposite/adjacent
opposite = -8
adjacent = 15


Use the pythagorean theorem to find the hypotenuse is 17 units
Pythagorean theorem is {{{a^2+b^2 = c^2}}}


We can form this diagram
*[illustration Screenshot_176.png]
The angle theta is in quadrant Q4 since 3pi/2 < theta < 2pi, where theta is in radians.


Then recall these trig ratios
sin(theta) = opposite/hypotenuse
cos(theta) = adjacent/hypotenuse
tan(theta) = opposite/adjacent


and we have these reciprocal ratios as well
csc(theta) = 1/sin = hypotenuse/opposite
sec(theta) = 1/cos = hypotenuse/adjacent
cot(theta) = 1/tan = adjacent/opposite


I'll let you finish things up.
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