Question 1198903

{{{nCr *q^(n - r)* p^r}}}, where {{{q = 1 - p}}}, the probability of failure of the event

{{{n=8}}}
{{{k=2}}}
{{{p=.3}}}
{{{q = 1 - p=1-.3=.7}}}

{{{(8C2) *.7^(8 - 2)* .3^2}}}

={{{28*.7^6* .3^2}}}

={{{28*0.117649* 0.09}}}

={{{0.296475}}}