Question 1198830


{{{f(t)=-3t^2 + 24t +60}}}

the ball maximum height will be at vertex

The formula to find the vertex is ({{{h}}}, {{{k}}}) = ({{{-b/2a}}}, {{{-D/4a}}}), where {{{D = b^2-4ac}}}

in your case {{{a=-3}}}, {{{b=24}}}, {{{c=60}}}

{{{-b/2a=-24/(2*(-3))=24/6=4}}}

{{{D = 24^2-4(-3)*60=1296}}}

then
 {{{-D/4a=-1296/(4*(-3))=1296/12=108}}}

the vertex is ({{{4}}}, {{{108}}}) 

the ball maximum height is  {{{108}}}


answer:

D) {{{108}}} feet