Question 1198766
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It depends if the diagram is this
{{{drawing(400,400,-10,10,-10,10,
line(-6,4,6,4),
line(6,4,6,-4),
line(6,-4,-6,-4),
line(-6,-4,-6,4),
arc(6,0,8,8,-90,90),
arc(-6,0,8,8,90,270),
locate(0,4,"97 m"),
locate(-5.5,0,"67 m")
)}}}


OR if it's this
{{{drawing(400,400,-10,10,-10,10,
line(-6,4,6,4),
line(6,4,6,-4),
line(6,-4,-6,-4),
line(-6,-4,-6,4),
arc(0,4,12,12,-180,0),
arc(0,-4,12,12,0,180),
locate(0,4,"97 m"),
locate(-5.5,0,"67 m")
)}}}



If it's the first diagram, then the semicircular portions can be joined together to form a circle of diameter 67 meters.
The circumference would be C = pi*d = 3.14*67 = 210.38 meters approximately.
This would be the distance along the curved portion of the track.
The straight line portions (two copies of 97) are added to get 210.38+97+97 = 404.38


So if your diagram is the first one I've shown above, then the answer is roughly 404.38 meters.
I used the approximation pi = 3.14; use more decimal digits of pi to get a more accurate answer.


If on the other hand the diagram was the second one I've shown above, then you'll have the two semicircular portions combine to a circle of diameter 97 meters.
C = pi*d = 3.14*97 = 304.58 is the curved portion of the track.
304.58+67+67 = 438.58 is the total perimeter.



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Summary:
404.38 meters is the approximate perimeter for the first diagram
438.58 meters is the approximate perimeter for the second diagram
Both approximations are based on pi = 3.14
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