Question 1198725
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The space shuttle traveled at v meters per second for L meters and was 5 seconds late 
for its reentry window. How fast should the shuttle have traveled to make it 
to the window on time?
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<pre>
Moving as described, the space shuttle covered L meters in  {{{L/v}}}  seconds and was 5 seconds late.


Hence, the right travel time should be  {{{L/v-5}}} seconds.

It dictates the necessary rate of the space shuttle  {{{L/(L/v - 5)}}} = {{{(Lv)/(L-5v)}}}.    <U>ANSWER</U>
</pre>

Solved.