<PRE><B>Question 1198535</B>
&lt;br&gt;
Tutor @MathTherapy has provided a clear solution using formal algebra.&lt;br&gt;
Note that the answer can be obtained informally, USING EXACTLY THE SAME CALCULATIONS, without formal algebra:&lt;br&gt;
If all 429 tickets had been adult tickets, the total cost would have been $429.&lt;br&gt;
The actual total cost was $372.50, which is $56.50 less than $429.&lt;br&gt;
The total cost decreases by $0.25 for each ticket that is a children&#39;s ticket instead of an adult ticket.&lt;br&gt;
So the number of children&#39;s tickets was&lt;br&gt;&lt;pre&gt;
  56.50   56.50*4   226
  ----- = ------- = --- = 226
   0.25    0.25*4    1&lt;/pre&gt;
ANSWER: 226 children&#39;s tickets, so 429-226 = 203 adult tickets&lt;br&gt;
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