Question 1198655
the average of four number is 40. the third number is 12 more than the second, the fourth is 8 less than the first. find the number?
-----------
The sum of the numbers is 4*40 = 160
1st # is f, then s, then t, then h
f + s + t + h = 160
t = s+12
h = f-8
-------------
f + s + s+12 + f-8 = 160
2f + 2s + 4 = 160
f + s = 78
-----
This is not sufficient info.