Question 1198638
f(x)=-3(x-4)(x+8)
x-intercepts (when y = 0) P(4,0) and P(-8,0)
y-intercept (when x = 0)  P(0, 96)
Equation of the axis of symmetry:  x = -2
Vertex: P (-2,108)
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f(x)=-3(x-4)(x+8) = -3(x^2 -4x - 32)
                  = 3((x+2)^2 -4 - 32)
                  = -3(x+2)^2 + 108
the vertex form of a Parabola opening up(a>0) or down(a<0), 
{{{y=a(x-h)^2 +k}}}. V(h, k)