Question 1198034
In quadrant IV, x is positive and y is negative.<br>
sin(A) is the y value, so sin(A) and its reciprocal csc(A) are negative in quadrant IV.<br>
cos(A) is the x value, so cos(A) and its reciprocal sec(A) are positive in quadrant IV.<br>
So in your problem the given value sec(t) is positive and the result sin(t) will be negative.<br>
{{{sin(t)=-sqrt(1-cos^2(t))=-sqrt(1-(1/sec^2(t)))}}}<br>