<PRE><B>Question 1198560</B>
&lt;br&gt;
The volume of the original cone in cubic meters is&lt;br&gt;
{{{V=(1/3)(pi)(r^2)(h)=(1/3)(pi)(0.6^2)(1.5)=0.18}}}&lt;br&gt;
The small cone cut off from the original cone has a height of 0.6m, which is 2/5 the height of the original cone.  That makes the volume of that small cone (2/5)^3 = 8/125 of the volume of the original cone.&lt;br&gt;
So then the volume of the frustum is 117/125 of the volume of the original cone.&lt;br&gt;
ANSWER: Volume of frustum = (0.18)(117/125) = 0.16848 cubic meters&lt;br&gt;
You can also find the volume using the formula for the volume of a frustum:&lt;br&gt;
{{{V=(1/3)(R^2+Rr+r^2)(h)}}}&lt;br&gt;
Where R and r are the radii of the two bases and h is the height of the frustum:&lt;br&gt;
{{{V=(1/3)((0.6^2)+(0.6*0.24)+(0.24^2))(0.9) = 0.16848}}}&lt;br&gt;
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