Question 1198601
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Not clear. Use parentheses.<br>
The expression as you show it:<br>
(-1)^n+1 (1/3n) --> {{{(-1)^n+1 (1/3n)}}}<br>
Other possibilities for what the expression is really supposed to be....<br>
(-1)^(n+1) (1/3n) --> {{{(-1)^(n+1) (1/3n)}}}<br>
(-1)^(n+1) ((1/3)n) --> {{{(-1)^(n+1) ((1/3)n)}}}<br>
All of those possibilities either do not converge or converge but not to any of the given answer choices.<br>
Re-post, showing the problem clearly.<br>