Question 1198602
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        I believe that your sequence/expression is    {{{2*(1/3)^(n-1)}}}.

        It is the only reasonable version for this context. 



<pre>
Then the sequence is an infinite geometric progression with the first term of 2
and the common ratio  r = {{{1/3}}}.


Use the standard formula for the sum of an infinite geometric sequence

    S = {{{a[1]/(1-r)}}}.


In your case, it gives  S = {{{2/(1-1/3)}}} = {{{2/((2/3))}}} = 3.    <U>ANSWER</U>
</pre>

Solved.


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In the future, use parentheses in your formulas, to show upper indexes ,

numerators and denominators for clear writing/reading.



In you case, the expression should be written in this form  2(1/3)^(n-1),


where the upper index (the degree) goes in parentheses.



Otherwise, tutors will have difficulties reading/interpreting your posts.