Question 1198604


{{{2cos(x)-1=0}}}, in the interval [{{{0}}}, {{{2pi}}}]


{{{2cos(x)-1=0}}}

{{{2cos(x)=1}}}

{{{cos(x)=1/2}}}

{{{x=cos^-1(1/2)}}}

{{{x=pi/3}}}



 solutions in the interval [{{{0}}}, {{{2pi}}}]

{{{x=pi/3}}}

{{{x = (5pi)/3}}}


answer:
E)