Question 1198581
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Basic vertex form:<br>
{{{(y-k)^2=(4p)(x-h)}}}<br>
In that form, the vertex is (h,k), and p is the directed distance (i.e., could be negative) from the directrix to the focus and from the focus to the vertex.  The y term is squared, so the parabola opens right or left.<br>
In your example, the vertex (h,k) is (3,-3); and 4p=4, so p=1.  So the focus is 1 unit to the right of the vertex, at (4,-3); and the directrix is 1 unit to the left of the vertex, at x=2.<br>
ANSWER: C)<br>
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Side note:<br>
I personally prefer the equivalent basic vertex form,<br>
{{{(x-h)=(1/(4p))(y-k)^2}}}<br>
because I prefer having the linear expression on the left side of the equation.<br>
But of course they are equivalent, so either form is fine.<br>