Question 1198570
 A wood man stuck 8k+5 logs of wood in a pile such that the pile contain k layers the top layer contain 8 logs, each layer contain 1 log more than the layer immediately above it.
 find the value of k.
Each layer adds one log after the top layer so there are 6 layers (+5)
:
 find the total number of logs
6 * 8 = 48, plus 5 would give you 53 logs
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I think I messed this one up, adding one to each layer after the top one
would be 8 + 9 + 10 + 11 etc, the total of this = 8k + 5, k is the no. layers
therefore 8k + 5 = total, then 8k = total - 5, I don't how you would get a multiple of 8 with that.
 If it was 8k + 6 however,
8k + 6 = 8 + 9 + 10 + 11 
8k + 6 = 38
8k = 38 - 6
8k = 32
k = 4
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Hope this helps, CK