Question 1198567


 {{{f(x)=2}}} where {{{f(x)=(3+2x^2)/(x^2+x-6)}}}


{{{2=(3+2x^2)/(x^2+x-6)}}}

{{{2(x^2+x-6)=(3+2x^2)}}}

{{{2x^2+2x-12=3+2x^2}}}

{{{2x^2+2x-12-3-2x^2=0}}}

{{{2x-15=0}}}

{{{2x=15}}}

{{{x=15/2}}}

{{{x=7.5}}}