Question 1198477
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The degree of the numerator is greater than the degree of the denominator, so there is no horizontal asymptote.<br>
The vertical asymptote(s) are where the denominator is 0:
6x+1 = 0 --> x = -1/6<br>
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NOTE:
If you are working on a problem like this, then you should know that the proper use of parentheses is important.  The function as you post it is not the function you meant:<br>
f(x)=x^2-25/6x+1 --> {{{f(x)=x^2-25/6x+1}}}<br>
The correct function is<br>
f(x)=(x^2-25)/(6x+1) --> {{{f(x)=(x^2-25)/(6x+1)}}}<br>