Question 114345
You don't know the diameter of the planet, so let's call that {{{D[p]}}} miles.  The first orbit is one mile above the planet, so we know that the diameter of the orbit is {{{D[p]+2}}}.  We had to add 2 because 1 mile of altitude adds 1 mile to the radius, and the diameter is twice that.  Now, if we move out to a point 2 miles above the surface, the diameter of the new orbit is {{{D[p]+4}}}.

We know that the distance travelled in the first orbit is the circumference of the circle with diameter {{{D[p]+2}}}, or {{{C[1]=(D[p]+2)*pi}}}, and the distance travelled in the second orbit is  {{{C[2]=(D[p]+4)*pi}}}.


Now we can subtract:  {{{C[2]-C[1]}}} => {{{((D[p]+4)pi)-((D[p]+2)pi)}}} => {{{(D[p]pi+4pi)-(D[p]pi+2pi)}}} => {{{2pi}}} miles.  Not too far, really, just a little over six and a quarter miles.


Hope this helps,
John