Question 1198429
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The solution from the other tutor shows a standard algebraic solution method for 2-part "mixture" problems like this.<br>
Here is an alternative which is often far less work, if the numbers in the problem are "nice".<br>
Look at the three prices per packet -- $2.48, $3.53, and $4.88 (on a number line, if it helps) -- and observe/calculate that $3.53 is 105/240 = 7/16 of the way from $2.48 to $4.88.<br>
That means 7/16 of the packets in the mixed assortment are the higher-priced hot pepper seeds.<br>
Then, since the mixed assortment contain 16 packets of seeds, it contains 7 packets of the hot pepper seeds and 9 packets of the sweet pepper seeds.<br>
ANSWER: 7 hot pepper packets, 9 sweet pepper<br>