Question 1198391
 In General {{{A(t) = P(1+r/n)^(nt)}}}
for example: in one year:  A = 3000(1.0025)^12 = $3091.25 rounded
             in two years:  A = 3000(1.025)^24 = $3185.27 rounded
             in 17 years;  A = 4992.70 rounded
A = Accumulated Amount = 5000
P= principal = 3000
r= annual rate = .03
n= periods per year = 12
t= years =    
{{{5000= 3000(1.0025)^(12t)}}}
  {{{ log( 5/3)/12log(1.0025) = t}}} = 17.0487 yr
compounding monthly:
1yr and .0487*12 = 17yr & 1mo (rounded up)