Question 1198342
<pre>
{{{ a + 1/ (b+2/c) = 17/5 }}}

Change the {{{17/5}}} to mixed number {{{3&2/5}}}

{{{ a + 1/ (b+2/c) = 3+2/5 }}}

Since a is the whole part, a = 3, so subtract 'a' from the
left side and '3' from the right side:

{{{1^""/ (b+2/c) = 2/5 }}}

Since c is the numerator of the fraction part of the mixed number,
c=2

{{{1^""/ (b+2/2) = 2/5 }}}

{{{1/ (b+1) = 2/5 }}}


Cross-multiply:

{{{5=2(b+1)}}}

{{{5=2b+2}}}

{{{3=2b}}}

{{{3/2=b}}}

So {{{a=3}}}, {{{b=3/2}}}, {{{c=2}}}, and {{{abc = (3)(3/2)(2) = (3)(3/cross(2))(cross(2)) = (3)(3) = 9}}}

Edwin</pre>